6(u-7)=4u-32

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Solution for 6(u-7)=4u-32 equation: 



6(u-7)=4u-32

We move all terms to the left:

6(u-7)-(4u-32)=0

We multiply parentheses

6u-(4u-32)-42=0

We get rid of parentheses

6u-4u+32-42=0

We add all the numbers together, and all the variables

2u-10=0

We move all terms containing u to the left, all other terms to the right

2u=10

u=10/2

u=5

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