7u+41=3(u+3)

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Solution for 7u+41=3(u+3) equation: 



7u+41=3(u+3)

We move all terms to the left:

7u+41-(3(u+3))=0



We calculate terms in parentheses: -(3(u+3)), so:

3(u+3)

We multiply parentheses

3u+9

Back to the equation:

-(3u+9)



We get rid of parentheses

7u-3u-9+41=0

We add all the numbers together, and all the variables

4u+32=0

We move all terms containing u to the left, all other terms to the right

4u=-32

u=-32/4

u=-8

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