(1/5)m+2/3-2=m-2/5

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Solution for (1/5)m+2/3-2=m-2/5 equation: 



(1/5)m+2/3-2=m-2/5

We move all terms to the left:

(1/5)m+2/3-2-(m-2/5)=0



Domain of the equation: 5)m!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+1/5)m-(+m-2/5)-2+2/3=0

We multiply parentheses

m^2-(+m-2/5)-2+2/3=0

We get rid of parentheses

m^2-m-2+2/5+2/3=0

We calculate fractions

There is no solution for this equation

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