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(G)=2/G-1
We move all terms to the left:
(G)-(2/G-1)=0
Domain of the equation: G-1)!=0We get rid of parentheses
G∈R
G-2/G+1=0
We multiply all the terms by the denominator
G*G+1*G-2=0
We add all the numbers together, and all the variables
G+G*G-2=0
Wy multiply elements
G^2+G-2=0
a = 1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*1}=\frac{-4}{2} =-2 $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*1}=\frac{2}{2} =1 $
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