(1/4*x)*20=20/4*x

Solution for (1/4*x)*20=20/4*x equation:

(1/4x)*20=20/4x

We move all terms to the left:

(1/4x)*20-(20/4x)=0


Domain of the equation: 4x)*20!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/4x)*20-(+20/4x)=0

We multiply parentheses

20x-(+20/4x)=0

We get rid of parentheses

20x-20/4x=0

We multiply all the terms by the denominator


20x*4x-20=0

Wy multiply elements

80x^2-20=0

a = 80; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·80·(-20)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*80}=\frac{-80}{160}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*80}=\frac{80}{160}
=1/2
$