2(9x-5)=3(6x+12)+4x

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Solution for 2(9x-5)=3(6x+12)+4x equation: 



2(9x-5)=3(6x+12)+4x

We move all terms to the left:

2(9x-5)-(3(6x+12)+4x)=0

We multiply parentheses

18x-(3(6x+12)+4x)-10=0



We calculate terms in parentheses: -(3(6x+12)+4x), so:

3(6x+12)+4x

We add all the numbers together, and all the variables

4x+3(6x+12)

We multiply parentheses

4x+18x+36

We add all the numbers together, and all the variables

22x+36

Back to the equation:

-(22x+36)



We get rid of parentheses

18x-22x-36-10=0

We add all the numbers together, and all the variables

-4x-46=0

We move all terms containing x to the left, all other terms to the right

-4x=46

x=46/-4

x=-11+1/2

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