(1/3)x+2=(1/6)x+4

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Solution for (1/3)x+2=(1/6)x+4 equation: 



(1/3)x+2=(1/6)x+4

We move all terms to the left:

(1/3)x+2-((1/6)x+4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6)x+4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)x-((+1/6)x+4)+2=0

We multiply parentheses

x^2-((+1/6)x+4)+2=0

We multiply all the terms by the denominator


x^2*6)x+4)-((+2*6)x+4)+1=0

We add all the numbers together, and all the variables

x^2*6)x+4)-(12x+4)+1=0

Wy multiply elements

6x^3=0

We do not support expression: x^3

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