200=20(4+y-3)

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Solution for 200=20(4+y-3) equation: 



200=20(4+y-3)

We move all terms to the left:

200-(20(4+y-3))=0

We add all the numbers together, and all the variables

-(20(y+1))+200=0



We calculate terms in parentheses: -(20(y+1)), so:

20(y+1)

We multiply parentheses

20y+20

Back to the equation:

-(20y+20)



We get rid of parentheses

-20y-20+200=0

We add all the numbers together, and all the variables

-20y+180=0

We move all terms containing y to the left, all other terms to the right

-20y=-180

y=-180/-20

y=+9

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