((108-5x)/8)+5x=108

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Solution for ((108-5x)/8)+5x=108 equation:



((108-5x)/8)+5x=108
We move all terms to the left:
((108-5x)/8)+5x-(108)=0
We add all the numbers together, and all the variables
((-5x+108)/8)+5x-108=0
We add all the numbers together, and all the variables
5x+((-5x+108)/8)-108=0
We multiply all the terms by the denominator
5x*8)+((-5x+108)-108*8)=0
We add all the numbers together, and all the variables
5x*8)+((-5x+108)=0
Wy multiply elements
40x^2=0
a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{80}=0$

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