3x2+30x+48=0

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Solution for 3x2+30x+48=0 equation:



3x^2+30x+48=0
a = 3; b = 30; c = +48;
Δ = b2-4ac
Δ = 302-4·3·48
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*3}=\frac{-48}{6} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*3}=\frac{-12}{6} =-2 $

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