(1/20)m+(2/5)=(9/10)

Solution for (1/20)m+(2/5)=(9/10) equation:

(1/20)m+(2/5)=(9/10)

We move all terms to the left:

(1/20)m+(2/5)-((9/10))=0


Domain of the equation: 20)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+1/20)m+(+2/5)-((+9/10))=0

We multiply parentheses

m^2+(+2/5)-((+9/10))=0

We get rid of parentheses

m^2+2/5-((+9/10))=0

We calculate fractions


m^2+()/()+()/()=0

We add all the numbers together, and all the variables

m^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation