(30-3y)2y=0

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Solution for (30-3y)2y=0 equation:



(30-3y)2y=0
We add all the numbers together, and all the variables
(-3y+30)2y=0
We multiply parentheses
-6y^2+60y=0
a = -6; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-6)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-6}=\frac{-120}{-12} =+10 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-6}=\frac{0}{-12} =0 $

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