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6a-4/2a-2=2
We move all terms to the left:
6a-4/2a-2-(2)=0
Domain of the equation: 2a!=0We add all the numbers together, and all the variables
a!=0/2
a!=0
a∈R
6a-4/2a-4=0
We multiply all the terms by the denominator
6a*2a-4*2a-4=0
Wy multiply elements
12a^2-8a-4=0
a = 12; b = -8; c = -4;
Δ = b2-4ac
Δ = -82-4·12·(-4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*12}=\frac{-8}{24} =-1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*12}=\frac{24}{24} =1 $
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