(1/(x+2))+(1/x-3)=0

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Solution for (1/(x+2))+(1/x-3)=0 equation: 



(1/(x+2))+(1/x-3)=0



Domain of the equation: (x+2))!=0

x∈R





Domain of the equation: x-3)!=0

x∈R



We get rid of parentheses

(1/(x+2))+1/x-3=0

We calculate fractions


((1*x)/3x^2+(1*(x+2)))/3x^2-3=0

We can not solve this equation

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