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16+2x=2(x-1)+8
We move all terms to the left:
16+2x-(2(x-1)+8)=0
We calculate terms in parentheses: -(2(x-1)+8), so:We get rid of parentheses
2(x-1)+8
We multiply parentheses
2x-2+8
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
2x-2x-6+16=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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