4(x+3)+2x=6(x-1)+18

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Solution for 4(x+3)+2x=6(x-1)+18 equation: 



4(x+3)+2x=6(x-1)+18

We move all terms to the left:

4(x+3)+2x-(6(x-1)+18)=0

We add all the numbers together, and all the variables

2x+4(x+3)-(6(x-1)+18)=0

We multiply parentheses

2x+4x-(6(x-1)+18)+12=0



We calculate terms in parentheses: -(6(x-1)+18), so:

6(x-1)+18

We multiply parentheses

6x-6+18

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

6x-(6x+12)+12=0

We get rid of parentheses

6x-6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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