(1-x)(1-2x)(1-3x)=0.25

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Solution for (1-x)(1-2x)(1-3x)=0.25 equation: 



(1-x)(1-2x)(1-3x)=0.25

We move all terms to the left:

(1-x)(1-2x)(1-3x)-(0.25)=0

We add all the numbers together, and all the variables

(-1x+1)(-2x+1)(-3x+1)-(0.25)=0

We add all the numbers together, and all the variables

(-1x+1)(-2x+1)(-3x+1)-0.25=0

We multiply parentheses ..

(+2x^2-1x-2x+1)(-3x+1)-0.25=0

We move all terms containing x to the left, all other terms to the right

(+2x^2-1x-2x+1)(-3x+1)=0.25

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