(1-t)=3(1-t)2-3(1-t)+6

Solution for (1-t)=3(1-t)2-3(1-t)+6 equation:

(1-t)=3(1-t)2-3(1-t)+6

We move all terms to the left:

(1-t)-(3(1-t)2-3(1-t)+6)=0

We add all the numbers together, and all the variables

(-1t+1)-(3(-1t+1)2-3(-1t+1)+6)=0

We get rid of parentheses

-1t-(3(-1t+1)2-3(-1t+1)+6)+1=0


We calculate terms in parentheses: -(3(-1t+1)2-3(-1t+1)+6), so:

3(-1t+1)2-3(-1t+1)+6

We multiply parentheses

-6t+3t+6-3+6

We add all the numbers together, and all the variables

-3t+9

Back to the equation:

-(-3t+9)


We get rid of parentheses

-1t+3t-9+1=0

We add all the numbers together, and all the variables

2t-8=0

We move all terms containing t to the left, all other terms to the right

2t=8

t=8/2

t=4