30+2(10-y)=20

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Solution for 30+2(10-y)=20 equation: 



30+2(10-y)=20

We move all terms to the left:

30+2(10-y)-(20)=0

We add all the numbers together, and all the variables

2(-1y+10)+30-20=0

We add all the numbers together, and all the variables

2(-1y+10)+10=0

We multiply parentheses

-2y+20+10=0

We add all the numbers together, and all the variables

-2y+30=0

We move all terms containing y to the left, all other terms to the right

-2y=-30

y=-30/-2

y=+15

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