5(x-2)+2x=7(x+4)-3x

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Solution for 5(x-2)+2x=7(x+4)-3x equation: 



5(x-2)+2x=7(x+4)-3x

We move all terms to the left:

5(x-2)+2x-(7(x+4)-3x)=0

We add all the numbers together, and all the variables

2x+5(x-2)-(7(x+4)-3x)=0

We multiply parentheses

2x+5x-(7(x+4)-3x)-10=0



We calculate terms in parentheses: -(7(x+4)-3x), so:

7(x+4)-3x

We add all the numbers together, and all the variables

-3x+7(x+4)

We multiply parentheses

-3x+7x+28

We add all the numbers together, and all the variables

4x+28

Back to the equation:

-(4x+28)



We add all the numbers together, and all the variables

7x-(4x+28)-10=0

We get rid of parentheses

7x-4x-28-10=0

We add all the numbers together, and all the variables

3x-38=0

We move all terms containing x to the left, all other terms to the right

3x=38

x=38/3

x=12+2/3

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