(1)/(3)x+10=(3)/(5)x

Solution for (1)/(3)x+10=(3)/(5)x equation:

(1)/(3)x+10=(3)/(5)x

We move all terms to the left:

(1)/(3)x+10-((3)/(5)x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(+3/5x)+10=0

We get rid of parentheses

1/3x-3/5x+10=0

We calculate fractions


5x/15x^2+(-9x)/15x^2+10=0

We multiply all the terms by the denominator


5x+(-9x)+10*15x^2=0

Wy multiply elements

150x^2+5x+(-9x)=0

We get rid of parentheses

150x^2+5x-9x=0

We add all the numbers together, and all the variables

150x^2-4x=0

a = 150; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·150·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*150}=\frac{0}{300}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*150}=\frac{8}{300}
=2/75
$