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(20+x)(50+x)=2275
We move all terms to the left:
(20+x)(50+x)-(2275)=0
We add all the numbers together, and all the variables
(x+20)(x+50)-2275=0
We multiply parentheses ..
(+x^2+50x+20x+1000)-2275=0
We get rid of parentheses
x^2+50x+20x+1000-2275=0
We add all the numbers together, and all the variables
x^2+70x-1275=0
a = 1; b = 70; c = -1275;
Δ = b2-4ac
Δ = 702-4·1·(-1275)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-100}{2*1}=\frac{-170}{2} =-85 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+100}{2*1}=\frac{30}{2} =15 $
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