(-8x-4)x=-1

Solution for (-8x-4)x=-1 equation:

(-8x-4)x=-1

We move all terms to the left:

(-8x-4)x-(-1)=0

We add all the numbers together, and all the variables

(-8x-4)x+1=0

We multiply parentheses

-8x^2-4x+1=0

a = -8; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·(-8)·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{3}}{2*-8}=\frac{4-4\sqrt{3}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{3}}{2*-8}=\frac{4+4\sqrt{3}}{-16}
$