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-(2x+8)x=-6
We move all terms to the left:
-(2x+8)x-(-6)=0
We add all the numbers together, and all the variables
-(2x+8)x+6=0
We multiply parentheses
-2x^2-8x+6=0
a = -2; b = -8; c = +6;
Δ = b2-4ac
Δ = -82-4·(-2)·6
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{7}}{2*-2}=\frac{8-4\sqrt{7}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{7}}{2*-2}=\frac{8+4\sqrt{7}}{-4} $
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