(-60-12b)=(1b+16)

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Solution for (-60-12b)=(1b+16) equation: 



(-60-12b)=(1b+16)

We move all terms to the left:

(-60-12b)-((1b+16))=0

We add all the numbers together, and all the variables

(-12b-60)-((b+16))=0

We get rid of parentheses

-12b-((b+16))-60=0



We calculate terms in parentheses: -((b+16)), so:

(b+16)

We get rid of parentheses

b+16

Back to the equation:

-(b+16)



We get rid of parentheses

-12b-b-16-60=0

We add all the numbers together, and all the variables

-13b-76=0

We move all terms containing b to the left, all other terms to the right

-13b=76

b=76/-13

b=-5+11/13

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