(60-12b)=(1b+16)

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Solution for (60-12b)=(1b+16) equation: 



(60-12b)=(1b+16)

We move all terms to the left:

(60-12b)-((1b+16))=0

We add all the numbers together, and all the variables

(-12b+60)-((b+16))=0

We get rid of parentheses

-12b-((b+16))+60=0



We calculate terms in parentheses: -((b+16)), so:

(b+16)

We get rid of parentheses

b+16

Back to the equation:

-(b+16)



We get rid of parentheses

-12b-b-16+60=0

We add all the numbers together, and all the variables

-13b+44=0

We move all terms containing b to the left, all other terms to the right

-13b=-44

b=-44/-13

b=3+5/13

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