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5(6x-5)(2x+5)=0
We multiply parentheses ..
5(+12x^2+30x-10x-25)=0
We multiply parentheses
60x^2+150x-50x-125=0
We add all the numbers together, and all the variables
60x^2+100x-125=0
a = 60; b = 100; c = -125;
Δ = b2-4ac
Δ = 1002-4·60·(-125)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-200}{2*60}=\frac{-300}{120} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+200}{2*60}=\frac{100}{120} =5/6 $
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