16x+2-4x+39=3(4x+2)+35

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Solution for 16x+2-4x+39=3(4x+2)+35 equation: 



16x+2-4x+39=3(4x+2)+35

We move all terms to the left:

16x+2-4x+39-(3(4x+2)+35)=0

We add all the numbers together, and all the variables

12x-(3(4x+2)+35)+41=0



We calculate terms in parentheses: -(3(4x+2)+35), so:

3(4x+2)+35

We multiply parentheses

12x+6+35

We add all the numbers together, and all the variables

12x+41

Back to the equation:

-(12x+41)



We get rid of parentheses

12x-12x-41+41=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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