(-6/7)x+26=-16

Solution for (-6/7)x+26=-16 equation:

(-6/7)x+26=-16

We move all terms to the left:

(-6/7)x+26-(-16)=0


Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-6/7)x+42=0

We multiply parentheses

-6x^2+42=0

a = -6; b = 0; c = +42;
Δ = b2-4ac
Δ = 02-4·(-6)·42
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{7}}{2*-6}=\frac{0-12\sqrt{7}}{-12}
=-\frac{12\sqrt{7}}{-12}
=-\frac{\sqrt{7}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{7}}{2*-6}=\frac{0+12\sqrt{7}}{-12}
=\frac{12\sqrt{7}}{-12}
=\frac{\sqrt{7}}{-1}
$