10(x+2)-4x=3(x+1)-12

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Solution for 10(x+2)-4x=3(x+1)-12 equation: 



10(x+2)-4x=3(x+1)-12

We move all terms to the left:

10(x+2)-4x-(3(x+1)-12)=0

We add all the numbers together, and all the variables

-4x+10(x+2)-(3(x+1)-12)=0

We multiply parentheses

-4x+10x-(3(x+1)-12)+20=0



We calculate terms in parentheses: -(3(x+1)-12), so:

3(x+1)-12

We multiply parentheses

3x+3-12

We add all the numbers together, and all the variables

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

6x-(3x-9)+20=0

We get rid of parentheses

6x-3x+9+20=0

We add all the numbers together, and all the variables

3x+29=0

We move all terms containing x to the left, all other terms to the right

3x=-29

x=-29/3

x=-9+2/3

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