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5/8x+7=x-11
We move all terms to the left:
5/8x+7-(x-11)=0
Domain of the equation: 8x!=0We get rid of parentheses
x!=0/8
x!=0
x∈R
5/8x-x+11+7=0
We multiply all the terms by the denominator
-x*8x+11*8x+7*8x+5=0
Wy multiply elements
-8x^2+88x+56x+5=0
We add all the numbers together, and all the variables
-8x^2+144x+5=0
a = -8; b = 144; c = +5;
Δ = b2-4ac
Δ = 1442-4·(-8)·5
Δ = 20896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20896}=\sqrt{16*1306}=\sqrt{16}*\sqrt{1306}=4\sqrt{1306}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-4\sqrt{1306}}{2*-8}=\frac{-144-4\sqrt{1306}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+4\sqrt{1306}}{2*-8}=\frac{-144+4\sqrt{1306}}{-16} $
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