(-6/7)+(5/3)x=-(1/2)

Solution for (-6/7)+(5/3)x=-(1/2) equation:

(-6/7)+(5/3)x=-(1/2)

We move all terms to the left:

(-6/7)+(5/3)x-(-(1/2))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/3)x+(-6/7)-(-(+1/2))=0

We multiply parentheses

5x^2+(-6/7)-(-(+1/2))=0

We get rid of parentheses

5x^2-6/7-(-(+1/2))=0

We calculate fractions


5x^2+()/()+()/()=0

We add all the numbers together, and all the variables

5x^2+2=0

a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation