((x+3)(x+3))-x(x+2)=9+2x

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Solution for ((x+3)(x+3))-x(x+2)=9+2x equation: 



((x+3)(x+3))-x(x+2)=9+2x

We move all terms to the left:

((x+3)(x+3))-x(x+2)-(9+2x)=0

We add all the numbers together, and all the variables

((x+3)(x+3))-x(x+2)-(2x+9)=0

We multiply parentheses

-x^2+((x+3)(x+3))-2x-(2x+9)=0

We get rid of parentheses

-x^2+((x+3)(x+3))-2x-2x-9=0

We multiply parentheses ..

-x^2+((+x^2+3x+3x+9))-2x-2x-9=0



We calculate terms in parentheses: +((+x^2+3x+3x+9)), so:

(+x^2+3x+3x+9)

We get rid of parentheses

x^2+3x+3x+9

We add all the numbers together, and all the variables

x^2+6x+9

Back to the equation:

+(x^2+6x+9)



We add all the numbers together, and all the variables

-1x^2-4x+(x^2+6x+9)-9=0

We get rid of parentheses

-1x^2+x^2-4x+6x+9-9=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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