2/3c-2=2-c

Solution for 2/3c-2=2-c equation:

2/3c-2=2-c

We move all terms to the left:

2/3c-2-(2-c)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R


We add all the numbers together, and all the variables

2/3c-(-1c+2)-2=0

We get rid of parentheses

2/3c+1c-2-2=0

We multiply all the terms by the denominator


1c*3c-2*3c-2*3c+2=0

Wy multiply elements

3c^2-6c-6c+2=0

We add all the numbers together, and all the variables

3c^2-12c+2=0

a = 3; b = -12; c = +2;
Δ = b2-4ac
Δ = -122-4·3·2
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{30}}{2*3}=\frac{12-2\sqrt{30}}{6}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{30}}{2*3}=\frac{12+2\sqrt{30}}{6}
$