4(y+6)=-4(2y-3)+2y

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Solution for 4(y+6)=-4(2y-3)+2y equation: 



4(y+6)=-4(2y-3)+2y

We move all terms to the left:

4(y+6)-(-4(2y-3)+2y)=0

We multiply parentheses

4y-(-4(2y-3)+2y)+24=0



We calculate terms in parentheses: -(-4(2y-3)+2y), so:

-4(2y-3)+2y

We add all the numbers together, and all the variables

2y-4(2y-3)

We multiply parentheses

2y-8y+12

We add all the numbers together, and all the variables

-6y+12

Back to the equation:

-(-6y+12)



We get rid of parentheses

4y+6y-12+24=0

We add all the numbers together, and all the variables

10y+12=0

We move all terms containing y to the left, all other terms to the right

10y=-12

y=-12/10

y=-1+1/5

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