(-2/3)w-4/9)=-4/5

Solution for (-2/3)w-4/9)=-4/5 equation:

(-2/3)w-4/9)=-4/5

We move all terms to the left:

(-2/3)w-4/9)-(-4/5)=0


Domain of the equation: 3)w!=0

w!=0/1

w!=0

w∈R


We multiply parentheses

-2w^2-4/9)-(-4/5)=0

We calculate fractions


-2w^2+()/()+()/()=0

We add all the numbers together, and all the variables

-2w^2+2=0

a = -2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-2)·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-2}=\frac{-4}{-4}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-2}=\frac{4}{-4}
=-1
$