-3(x+2)-5=x-7-4(x+1)

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Solution for -3(x+2)-5=x-7-4(x+1) equation: 



-3(x+2)-5=x-7-4(x+1)

We move all terms to the left:

-3(x+2)-5-(x-7-4(x+1))=0

We multiply parentheses

-3x-(x-7-4(x+1))-6-5=0



We calculate terms in parentheses: -(x-7-4(x+1)), so:

x-7-4(x+1)

determiningTheFunctionDomain
x-4(x+1)-7

We multiply parentheses

x-4x-4-7

We add all the numbers together, and all the variables

-3x-11

Back to the equation:

-(-3x-11)



We add all the numbers together, and all the variables

-3x-(-3x-11)-11=0

We get rid of parentheses

-3x+3x+11-11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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