8(v+4)-2v=2(3v+2)-5

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Solution for 8(v+4)-2v=2(3v+2)-5 equation: 



8(v+4)-2v=2(3v+2)-5

We move all terms to the left:

8(v+4)-2v-(2(3v+2)-5)=0

We add all the numbers together, and all the variables

-2v+8(v+4)-(2(3v+2)-5)=0

We multiply parentheses

-2v+8v-(2(3v+2)-5)+32=0



We calculate terms in parentheses: -(2(3v+2)-5), so:

2(3v+2)-5

We multiply parentheses

6v+4-5

We add all the numbers together, and all the variables

6v-1

Back to the equation:

-(6v-1)



We add all the numbers together, and all the variables

6v-(6v-1)+32=0

We get rid of parentheses

6v-6v+1+32=0

We add all the numbers together, and all the variables

33!=0

There is no solution for this equation

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