((x-5)+(2x-3))/2=x

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Solution for ((x-5)+(2x-3))/2=x equation: 



((x-5)+(2x-3))/2=x

We move all terms to the left:

((x-5)+(2x-3))/2-(x)=0

We add all the numbers together, and all the variables

-1x+((x-5)+(2x-3))/2=0

We multiply all the terms by the denominator


-1x*2+((x-5)+(2x-3))=0



We calculate terms in parentheses: +((x-5)+(2x-3)), so:

(x-5)+(2x-3)

We get rid of parentheses

x+2x-5-3

We add all the numbers together, and all the variables

3x-8

Back to the equation:

+(3x-8)



Wy multiply elements

-2x+(3x-8)=0

We get rid of parentheses

-2x+3x-8=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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