((x+1)/3)+((3x+7)/24)=2

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Solution for ((x+1)/3)+((3x+7)/24)=2 equation:



((x+1)/3)+((3x+7)/24)=2
We move all terms to the left:
((x+1)/3)+((3x+7)/24)-(2)=0
We calculate fractions
(24x+24)/()+(9x+21)/()-2=0
We multiply all the terms by the denominator
(24x+24)+(9x+21)-2*()=0
We add all the numbers together, and all the variables
(24x+24)+(9x+21)=0
We get rid of parentheses
24x+9x+24+21=0
We add all the numbers together, and all the variables
33x+45=0
We move all terms containing x to the left, all other terms to the right
33x=-45
x=-45/33
x=-1+4/11

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