(1/4)(7x-8)=6

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Solution for (1/4)(7x-8)=6 equation: 



(1/4)(7x-8)=6

We move all terms to the left:

(1/4)(7x-8)-(6)=0



Domain of the equation: 4)(7x-8)!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)(7x-8)-6=0

We multiply parentheses ..

(+7x^2+1/4*-8)-6=0

We multiply all the terms by the denominator


(+7x^2+1-6*4*-8)=0

We get rid of parentheses

7x^2+1-8-6*4*=0

We add all the numbers together, and all the variables

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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