8(x-9)-9(x-8)=x+-8(x-4)

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Solution for 8(x-9)-9(x-8)=x+-8(x-4) equation: 



8(x-9)-9(x-8)=x+-8(x-4)

We move all terms to the left:

8(x-9)-9(x-8)-(x+-8(x-4))=0

We use the square of the difference formula

8(x-9)-9(x-8)-(x-8(x-4))=0

We multiply parentheses

8x-9x-(x-8(x-4))-72+72=0



We calculate terms in parentheses: -(x-8(x-4)), so:

x-8(x-4)

We multiply parentheses

x-8x+32

We add all the numbers together, and all the variables

-7x+32

Back to the equation:

-(-7x+32)



We add all the numbers together, and all the variables

-1x-(-7x+32)=0

We get rid of parentheses

-1x+7x-32=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3

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