((g-11)(g-8))/2=35

Solution for ((g-11)(g-8))/2=35 equation:

((g-11)(g-8))/2=35

We move all terms to the left:

((g-11)(g-8))/2-(35)=0

We multiply parentheses ..

((+g^2-8g-11g+88))/2-35=0

We multiply all the terms by the denominator


((+g^2-8g-11g+88))-35*2=0


We calculate terms in parentheses: +((+g^2-8g-11g+88)), so:

(+g^2-8g-11g+88)

We get rid of parentheses

g^2-8g-11g+88

We add all the numbers together, and all the variables

g^2-19g+88

Back to the equation:

+(g^2-19g+88)


We add all the numbers together, and all the variables

(g^2-19g+88)-70=0

We get rid of parentheses

g^2-19g+88-70=0

We add all the numbers together, and all the variables

g^2-19g+18=0

a = 1; b = -19; c = +18;
Δ = b2-4ac
Δ = -192-4·1·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-17}{2*1}=\frac{2}{2}
=1
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+17}{2*1}=\frac{36}{2}
=18
$