e2=e-e2

Solution for e2=e-e2 equation:

e2=e-e2

We move all terms to the left:

e2-(e-e2)=0

We add all the numbers together, and all the variables

-(+e-1e^2)+e2=0

We add all the numbers together, and all the variables

e^2-(+e-1e^2)=0

We get rid of parentheses

e^2+1e^2-e=0

We add all the numbers together, and all the variables

2e^2-1e=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$