((4x-4)/8)-((4x-2)/6)=1/3

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Solution for ((4x-4)/8)-((4x-2)/6)=1/3 equation: 



((4x-4)/8)-((4x-2)/6)=1/3

We move all terms to the left:

((4x-4)/8)-((4x-2)/6)-(1/3)=0

We add all the numbers together, and all the variables

((4x-4)/8)-((4x-2)/6)-(+1/3)=0

We get rid of parentheses

((4x-4)/8)-((4x-2)/6)-1/3=0

We calculate fractions


(((4x-4)*6)*3)/()+(-((4x-2)*8)*3)/()+()/()=0



We calculate terms in parentheses: +(((4x-4)*6)*3)/(), so:

((4x-4)*6)*3)/(

We multiply all the terms by the denominator


((4x-4)*6)*3)



We calculate terms in parentheses: +((4x-4)*6)*3), so:

(4x-4)*6)*3

We multiply parentheses

12x+

We add all the numbers together, and all the variables

12x

Back to the equation:

+(12x)



Back to the equation:

+(12x)





We calculate terms in parentheses: +(-((4x-2)*8)*3)/(), so:

-((4x-2)*8)*3)/(

We multiply all the terms by the denominator


-((4x-2)*8)*3)



We calculate terms in parentheses: -((4x-2)*8)*3), so:

(4x-2)*8)*3

We multiply parentheses

12x+

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



Back to the equation:

+(-12x)



We add all the numbers together, and all the variables

12x+(-12x)+1=0

We get rid of parentheses

12x-12x+1=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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