((4x+2)/3)-((x-7)/4)=3

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Solution for ((4x+2)/3)-((x-7)/4)=3 equation: 



((4x+2)/3)-((x-7)/4)=3

We move all terms to the left:

((4x+2)/3)-((x-7)/4)-(3)=0

We calculate fractions


(16x+8)/()+(-3x+21)/()-3=0

We multiply all the terms by the denominator


(16x+8)+(-3x+21)-3*()=0

We add all the numbers together, and all the variables

(16x+8)+(-3x+21)=0

We get rid of parentheses

16x-3x+8+21=0

We add all the numbers together, and all the variables

13x+29=0

We move all terms containing x to the left, all other terms to the right

13x=-29

x=-29/13

x=-2+3/13

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