88=n*(n-3)

Solution for 88=n*(n-3) equation:

88=n(n-3)

We move all terms to the left:

88-(n(n-3))=0


We calculate terms in parentheses: -(n(n-3)), so:

n(n-3)

We multiply parentheses

n^2-3n

Back to the equation:

-(n^2-3n)


We get rid of parentheses

-n^2+3n+88=0

We add all the numbers together, and all the variables

-1n^2+3n+88=0

a = -1; b = 3; c = +88;
Δ = b2-4ac
Δ = 32-4·(-1)·88
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-19}{2*-1}=\frac{-22}{-2}
=+11
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+19}{2*-1}=\frac{16}{-2}
=-8
$