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((2/3)x)+((1/4)x)=(x+2)
We move all terms to the left:
((2/3)x)+((1/4)x)-((x+2))=0
Domain of the equation: 3)x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((+2/3)x)+((+1/4)x)-((x+2))=0
We calculate fractions
-((x+2))+8x/3x)*4)x))+3x/3x)*4)x))=0
We calculate terms in parentheses: -((x+2)), so:We can not solve this equation
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
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