z/5-7=4(1/3)

Solution for z/5-7=4(1/3) equation:

z/5-7=4(1/3)

We move all terms to the left:

z/5-7-(4(1/3))=0

We add all the numbers together, and all the variables

z/5-7-(4(+1/3))=0

We calculate fractions


3z^2/()-7+()/()=0

We add all the numbers together, and all the variables

3z^2/()-6=0

We multiply all the terms by the denominator


3z^2-6*()=0

We add all the numbers together, and all the variables

3z^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{6}=0$