49+3(y+9)=2(6y+17)+4y

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Solution for 49+3(y+9)=2(6y+17)+4y equation: 



49+3(y+9)=2(6y+17)+4y

We move all terms to the left:

49+3(y+9)-(2(6y+17)+4y)=0

We multiply parentheses

3y-(2(6y+17)+4y)+27+49=0



We calculate terms in parentheses: -(2(6y+17)+4y), so:

2(6y+17)+4y

We add all the numbers together, and all the variables

4y+2(6y+17)

We multiply parentheses

4y+12y+34

We add all the numbers together, and all the variables

16y+34

Back to the equation:

-(16y+34)



We add all the numbers together, and all the variables

3y-(16y+34)+76=0

We get rid of parentheses

3y-16y-34+76=0

We add all the numbers together, and all the variables

-13y+42=0

We move all terms containing y to the left, all other terms to the right

-13y=-42

y=-42/-13

y=3+3/13

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